The age of a mother 10 years ago was thrice the age of her son. 10 years hence, the mother's age will be twice that of 9 her son. The ratio of their present ages is :

The present age of A and B are in the ratio 5: 4. After 10 years the ratio becomes 7: 6. Find the present age of A.

A is 4 years younger than B. B is 12 years younger than C. 4 years hence the ratio between C and A is 9:5, Find the age of B.

Four years ago, the age ratio of A and B was 2: 3 and after four years this ratio will be 5: 7. What is his present age?

A mother is 28 years older than twice the age of her son. Five years later, the mother will be 10 years older than thrice the age of her son. What is mother’s present age?

There are some friends, all less than 20 years. When paired amongst themselves they realize that the sum of their ages is a multiple of 5. If their ages are distinct prime numbers, then the number of possible pairs are: 

Seema is 8 years elder than his sister and 7 years younger than her brother Raj. When Raj was born, her father’s age was 30 and when Seema’s sister was born his mother’s age was 34. Find the difference between ages of Seema’s father and his mother?

The respective ratio of, the present age of a Monika and Divya is 7 : 1. Four years ago the respective ratio of their age was 19 : 1. What will be the Monika’s age four years from now?