A root of equation $$({ax}^2+bx+c)$$ (where a, b and c are rational numbers) is 5 +3√3. What is the value of $$({a}^2+b^2+c^2) / (a+b+c) ? $$

The value of 64 ÷ 2 ×(9÷3) ×3÷9-32 is:

Direction: Equation number I and II are given. You have to solve both the question and answer.
$$ {I.x^{2}={144}}$$
$$ {II.y^{2}-24y+144=0}$$

$$ {I.2x^{2}-{9x}+10=0}$$
$$ {II.2y^{2}-13y+20=0}$$

$${I. \sqrt{200x}+\sqrt{102}=0}$$
$${II.\sqrt{160y}+\sqrt{200}=0}$$

$${I.{(13)^{2}}-14+28=x}$$
$${II.{(16)^{2}}-8×7=y}$$

In equation $$ {x^{2}-24x+k=0}$$ the first root is x=2 then find out  the second root of equation.

$$ ({2+\sqrt{5}})$$ and $$ ({2-\sqrt{5}})$$ is a quadratic equation with roots.