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Q: Three fair coins are tossed simultaneously. Find the probability of getting more heads than the number of tails

  • 1
    2
  • 2
    7/8
  • 3
    5/8
  • 4
    1/2
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Answer : 4. "1/2"
Explanation :

Answer: D) 1/2 Explanation: S = { HHH, HHT, HTH, HTT, THH, THT, TTH, TTT } => n(S) = 8 E = { HHH, HHT, HTH, THH } => n(E) = 4 P(E) = 4/8 = 1/2

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