Aptitude Questions Practice Question and Answer
8Q: Find value of log27 +log 8 +log1000log 120 1415 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: What is the number of digits in 333? Given that log3 = 0.47712? 4759 05b5cc7d0e4d2b41977751209
5b5cc7d0e4d2b41977751209- 112false
- 213true
- 314false
- 415false
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Answer : 2. "13"
Explanation :
Answer: B) 13 Explanation: Let Let x=333 = 333 Then, logx = 33 log3 = 27 x 0.47712 = 12.88224 Since the characteristic in the resultant value of log x is 12 ∴The number of digits in x is (12 + 1) = 13 Hence the required number of digits in 333is 13.
Q: For x∈N, x>1, and p=logxx+1, q=logx+1x+2 then which one of the following is correct? 5293 25b5cc7d0e4d2b419777511ff
5b5cc7d0e4d2b419777511ff- 1p < qfalse
- 2p = qfalse
- 3p > qtrue
- 4can't be determinedfalse
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Answer : 3. "p > q"
Explanation :
Answer: C) p > q Explanation: kl>k+1l+1 for (k,l) > 0 and k > l Let k = x+1 and l = x Therefore, x+1x>(x+1)+1(x)+1 (x + 1) > x Therefore, log(x+1)log(x)>log(x+2)log(x+1) ⇒logxx+1 >logx+1x+2
Q: The Value of logtan10+logtan20+⋯⋯+logtan890 is 1016 15b5cc7d0e4d2b41977751204
5b5cc7d0e4d2b41977751204- 1-1false
- 20true
- 31/2false
- 41false
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Answer : 2. "0"
Explanation :
Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450 = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1 ∵ tan(90-θ)=cotθ and tan 450=1 = log 1 + log 1 +.....+log 1 = 0.
Q: An industrial loom weaves 1.14 meters of cloth every second. Approximately, how much time will it take to weave 52 meters of cloth ? 2143 15b5cc783e4d2b41977750219
5b5cc783e4d2b41977750219- 129.32 secfalse
- 242.51 secfalse
- 339.25 secfalse
- 445.61 sectrue
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Answer : 4. "45.61 sec"
Explanation :
Answer: D) 45.61 sec Explanation: Given loom weaves 1.14 mts of cloth in one second then 52 mts of cloth can be weaved by loom in, 1.14 ----- 1 52.0 ------? ⇒521.14= 45.61 sec
Q: If log 64 = 1.8061, then the value of log 16 will be (approx)? 3724 05b5cc77ae4d2b41977750160
5b5cc77ae4d2b41977750160- 11.9048false
- 21.2040true
- 30.9840false
- 41.4521false
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Answer : 2. "1.2040"
Explanation :
Answer: B) 1.2040 Explanation: Given that, log 64 = 1.8061 i.e log43=1.8061 --> 3 log 4 = 1.8061 --> log 4 = 0.6020 --> 2 log 4 = 1.2040 ⇒log42=1.2040 Therefore, log 16 = 1.2040
Q: If a2+b2 = c2 , then 1logc+ab + 1logc-ab = ? 1603 15b5cc761e4d2b4197774fd67
5b5cc761e4d2b4197774fd67- 11false
- 22true
- 34false
- 48false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: Given a2 + b2 = c2 Now 1logc+ab + 1logc-ab = logbc+a + logbc-a = logbc2-a2 = 2logbb = 2
Q: If log72 = m, then log4928 is equal to ? 1560 05b5cc761e4d2b4197774fd5d
5b5cc761e4d2b4197774fd5d- 11/(1+2m)false
- 2(1+2m)/2true
- 32m/(2m+1)false
- 4(2m+1)/2mfalse
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Answer : 2. "(1+2m)/2"
Explanation :
Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4 = 12+122log72= 12+log72= 12 + m= 1+2m2.