In an isosceles triangles ABC, AB=AC the median drawn on the same arms are perpendicular to each other find AB/BC?
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Q:
In an isosceles triangles ABC, AB=AC the median drawn on the same arms are perpendicular to each other find AB/BC?
- 1$${\sqrt{5\over{2}}}$$true
- 2$${5\over2}$$false
- 3$${2\over5}$$false
- 4$${5\over {\sqrt {3}}}$$false
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