If $$ {3\sqrt{{1-a}\over{a}}}+9={19-3\sqrt{{a}\over{1-a}}}$$, then what is the value of a?
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Q:
If $$ {3\sqrt{{1-a}\over{a}}}+9={19-3\sqrt{{a}\over{1-a}}}$$, then what is the value of a?
- 1$${3\over10},{7\over10}$$false
- 2$${1\over10},{9\over10}$$true
- 3$${2\over5},{3\over5}$$false
- 4$${1\over5},{4\over5}$$false
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