If $$ {3^{4x-y}={3^{x+y}=\sqrt{27}}}$$, then the value of y is:
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Q:
If $$ {3^{4x-y}={3^{x+y}=\sqrt{27}}}$$, then the value of y is:
- 1$$ {9\over 10}$$true
- 2$$ {3\over 2}$$false
- 32false
- 4$$ {3\over 4}$$false
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