Reasoning Practice Question and Answer
8Q: Insurance Company X is considering issuing a new policy to cover services required by elderly people who suffer from diseases that afflict the elderly. Premiums for the policy must be low enough to attract customers; therefore, Company X is concerned that the income from the policies would not be sufficient to pay for the claims that would be made. Which of the following strategies would be most likely to minimize Company X's losses on the policies? 8047 05be00689c1927812d6e1a02a
5be00689c1927812d6e1a02a- 1Attracting middle-aged customers unlikely to submit claims for benefits for many years.true
- 2Insuring only those individuals who did not suffer any serious diseases as children.false
- 3Including a greater number of services in the policy than are included in other policies of lower cost.false
- 4Insuring only those individuals who were rejected by other companies for similar policies.false
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Answer : 1. "Attracting middle-aged customers unlikely to submit claims for benefits for many years."
Q: Find the odd one out?
61, 66, 83, 121, 185 1677 25b5cc601e4d2b4197774b494
5b5cc601e4d2b4197774b494- 1185false
- 2121true
- 383false
- 466false
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Answer : 2. "121"
Explanation :
Answer: B) 121 Explanation: Given number series is 61, 66, 83, 121, 185 Here the given series follows a pattern that, 6161 + 22 + 1 = 6666 + 42 + 1 = 8383 + 62 + 1 = 120 (not 121)120 + 82 + 1 = 185 Hence, the odd man in the given series is 121.
Q: Arrange the words given below in a meaningful sequence. 11371 05bdbeff6e128556fff7c0de8
5bdbeff6e128556fff7c0de8- 13, 1, 2, 4, 5false
- 21, 2, 4, 3, 5false
- 35, 4, 3, 2, 1false
- 43, 1, 4, 5, 2true
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Answer : 4. "3, 1, 4, 5, 2"
Q: When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less than 12? 1275 05b5cc5ffe4d2b4197774b427
5b5cc5ffe4d2b4197774b427- 135/36true
- 217/36false
- 315/36false
- 41/36false
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Answer : 1. "35/36"
Explanation :
Answer: A) 35/36 Explanation: When two dice are thrown simultaneously, the probability is n(S) = 6x6 = 36 Required, the sum of the two numbers that turn up is less than 12 That can be done as n(E) = { (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)(6,1), (6,2), (6,3), (6,4), (6,5) } = 35 Hence, required probability = n(E)/n(S) = 35/36.
Q: Complete the given number series?
8, 14, 24, 40, ?
4331 05b5cc601e4d2b4197774b48a
5b5cc601e4d2b4197774b48a8, 14, 24, 40, ?
- 165true
- 284false
- 396false
- 4102false
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Answer : 1. "65"
Explanation :
Answer: A) 65 Explanation: The given number series is 8, 14, 24, 40, ? . It follows a pattern that, 8 8 x 1.5 + 2 = 14 14 x 1.5 + 3 = 24 24 x 1.5 + 4 = 40 40 x 1.5 + 5 = 65 Hence, the next number in the given number series is 65.
Q: Some boys are sitting in a row. P is sitting fourteenth from the left and Q is seventh from the right. If there are four boys between P and Q, how many boys are there in the row ? 3269 15b5cc6f8e4d2b4197774f059
5b5cc6f8e4d2b4197774f059- 126false
- 224false
- 325true
- 422false
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Answer : 3. "25"
Q: In a row of girls, Nithya and Suganya occupy the ninth place from the right end and tenth place from the left end, respectively. If they interchange their places, then Nithya and Suganya occupy seventeenth place from the right and eighteenth place from the left respectively. How many girls are there in the row? 59032 05bd2f9cec407ca5b8c184c86
5bd2f9cec407ca5b8c184c86- 122false
- 224false
- 326true
- 428false
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Answer : 3. "26"
Q: Find the odd one out in question 1832 15bdc0c39710b5551ccc2f862
5bdc0c39710b5551ccc2f862- 1profit: lossfalse
- 2wise: foolishfalse
- 3virtue: vicefalse
- 4seduce: attracttrue
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